elementary number theory - Prove that $\gcd(a^n - 1, a^m - 1) = a^{\gcd(n, m)} - 1$ - Mathematics Stack Exchange
For all $a, m, n \in \mathbb{Z}^+$, $$\gcd(a^n - 1, a^m - 1) = a^{\gcd(n, m)} - 1$$| Mathematics Stack Exchange
In honor of the 92d anniversary of William Luther Pierce’s birth, we present this American Dissident Voices broadcast which includes a long-lost essay by Dr. Pierce. https://audio.nationalvanguard.com/ADV%202016-0521jol.mp3 American Dissident Voices broadcast of 4 October 2025 presented…| National Vanguard
College students today face an ideological onslaught from educators who are more concerned with creating “good citizens” than teaching them real knowledge. And it’s time for a new approach. I’m running a program for high school and college students this summer because of a first grade perplexity — and Ayn Rand. When I was kid … Continue reading "Students Need Mental Ammunition"| Marsha Familaro Enright
For all $a, m, n \in \mathbb{Z}^+$, $$\gcd(a^n - 1, a^m - 1) = a^{\gcd(n, m)} - 1$$| Mathematics Stack Exchange
